Base | Representation |
---|---|
bin | 111100101000110110… |
… | …1111000110000000011 |
3 | 110110010020220112001102 |
4 | 1321101231320300003 |
5 | 4113142310033212 |
6 | 135453334325015 |
7 | 12256654520333 |
oct | 1712155706003 |
9 | 413106815042 |
10 | 130220002307 |
11 | 5025388411a |
12 | 212a24b976b |
13 | c383643305 |
14 | 64347b70c3 |
15 | 35c231e5c2 |
hex | 1e51b78c03 |
130220002307 has 2 divisors, whose sum is σ = 130220002308. Its totient is φ = 130220002306.
The previous prime is 130220002291. The next prime is 130220002427. The reversal of 130220002307 is 703200022031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130220002307 - 24 = 130220002291 is a prime.
It is not a weakly prime, because it can be changed into another prime (130220002207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110001153 + 65110001154.
It is an arithmetic number, because the mean of its divisors is an integer number (65110001154).
Almost surely, 2130220002307 is an apocalyptic number.
130220002307 is a deficient number, since it is larger than the sum of its proper divisors (1).
130220002307 is an equidigital number, since it uses as much as digits as its factorization.
130220002307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 20.
Adding to 130220002307 its reverse (703200022031), we get a palindrome (833420024338).
The spelling of 130220002307 in words is "one hundred thirty billion, two hundred twenty million, two thousand, three hundred seven".
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