Base | Representation |
---|---|
bin | 10010111100110001001… |
… | …111000001101010010000 |
3 | 11121111012122010120221110 |
4 | 102330301033001222100 |
5 | 132313401441110412 |
6 | 2434120053053320 |
7 | 163036520555205 |
oct | 22746117015220 |
9 | 4544178116843 |
10 | 1302201113232 |
11 | 462295642138 |
12 | 190460627240 |
13 | 95a491286c6 |
14 | 47053a35cac |
15 | 23d172b1d3c |
hex | 12f313c1a90 |
1302201113232 has 80 divisors (see below), whose sum is σ = 3387754598400. Its totient is φ = 431006928000.
The previous prime is 1302201113221. The next prime is 1302201113251. The reversal of 1302201113232 is 2323111022031.
It is a junction number, because it is equal to n+sod(n) for n = 1302201113199 and 1302201113208.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17350507 + ... + 17425397.
It is an arithmetic number, because the mean of its divisors is an integer number (42346932480).
Almost surely, 21302201113232 is an apocalyptic number.
1302201113232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1302201113232 is an abundant number, since it is smaller than the sum of its proper divisors (2085553485168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1302201113232 is a wasteful number, since it uses less digits than its factorization.
1302201113232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77452 (or 77446 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1302201113232 its reverse (2323111022031), we get a palindrome (3625312135263).
The spelling of 1302201113232 in words is "one trillion, three hundred two billion, two hundred one million, one hundred thirteen thousand, two hundred thirty-two".
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