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13022021312057 is a prime number
BaseRepresentation
bin1011110101111110110011…
…1101000101111000111001
31201002220010001111002101202
42331133230331011320321
53201323044423441212
643410122313423545
72512544553562352
oct275375475057071
951086101432352
1013022021312057
11417067660244a
12156390870abb5
13735c8205ca94
143303aa952d29
15178aecac50c2
hexbd7ecf45e39

13022021312057 has 2 divisors, whose sum is σ = 13022021312058. Its totient is φ = 13022021312056.

The previous prime is 13022021312029. The next prime is 13022021312299. The reversal of 13022021312057 is 75021312022031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12916411911481 + 105609400576 = 3593941^2 + 324976^2 .

It is a cyclic number.

It is not a de Polignac number, because 13022021312057 - 220 = 13022020263481 is a prime.

It is not a weakly prime, because it can be changed into another prime (13022021312857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511010656028 + 6511010656029.

It is an arithmetic number, because the mean of its divisors is an integer number (6511010656029).

Almost surely, 213022021312057 is an apocalyptic number.

It is an amenable number.

13022021312057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022021312057 is an equidigital number, since it uses as much as digits as its factorization.

13022021312057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 13022021312057 its reverse (75021312022031), we get a palindrome (88043333334088).

The spelling of 13022021312057 in words is "thirteen trillion, twenty-two billion, twenty-one million, three hundred twelve thousand, fifty-seven".