Base | Representation |
---|---|
bin | 1011110101111110110011… |
… | …1111110000010111011011 |
3 | 1201002220010002210120020202 |
4 | 2331133230333300113123 |
5 | 3201323100113312311 |
6 | 43410122340412415 |
7 | 2512544562531215 |
oct | 275375477602733 |
9 | 51086102716222 |
10 | 13022022010331 |
11 | 4170676a3a034 |
12 | 15639089a710b |
13 | 735c82245869 |
14 | 3303aaa955b5 |
15 | 178aecbb1e3b |
hex | bd7ecff05db |
13022022010331 has 2 divisors, whose sum is σ = 13022022010332. Its totient is φ = 13022022010330.
The previous prime is 13022022010313. The next prime is 13022022010337. The reversal of 13022022010331 is 13301022022031.
Together with previous prime (13022022010313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13022022010331 - 210 = 13022022009307 is a prime.
It is a super-2 number, since 2×130220220103312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13022022010337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511011005165 + 6511011005166.
It is an arithmetic number, because the mean of its divisors is an integer number (6511011005166).
Almost surely, 213022022010331 is an apocalyptic number.
13022022010331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022022010331 is an equidigital number, since it uses as much as digits as its factorization.
13022022010331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13022022010331 its reverse (13301022022031), we get a palindrome (26323044032362).
The spelling of 13022022010331 in words is "thirteen trillion, twenty-two billion, twenty-two million, ten thousand, three hundred thirty-one".
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