Base | Representation |
---|---|
bin | 1011110101111110110110… |
… | …0110101111011110100011 |
3 | 1201002220010211000210102101 |
4 | 2331133231212233132203 |
5 | 3201323110222332212 |
6 | 43410123343431231 |
7 | 2512545045435112 |
oct | 275375546573643 |
9 | 51086124023371 |
10 | 13022032230307 |
11 | 417068178a4a1 |
12 | 15639102b5517 |
13 | 735c843b3599 |
14 | 3303ac195c79 |
15 | 178aeda30157 |
hex | bd7ed9af7a3 |
13022032230307 has 2 divisors, whose sum is σ = 13022032230308. Its totient is φ = 13022032230306.
The previous prime is 13022032230299. The next prime is 13022032230359. The reversal of 13022032230307 is 70303223022031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13022032230307 - 23 = 13022032230299 is a prime.
It is a super-3 number, since 3×130220322303073 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13022032240307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511016115153 + 6511016115154.
It is an arithmetic number, because the mean of its divisors is an integer number (6511016115154).
Almost surely, 213022032230307 is an apocalyptic number.
13022032230307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022032230307 is an equidigital number, since it uses as much as digits as its factorization.
13022032230307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 28.
Adding to 13022032230307 its reverse (70303223022031), we get a palindrome (83325255252338).
The spelling of 13022032230307 in words is "thirteen trillion, twenty-two billion, thirty-two million, two hundred thirty thousand, three hundred seven".
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