Base | Representation |
---|---|
bin | 11101100110111110001001… |
… | …100010111111011110011011 |
3 | 122002002001020201212112201211 |
4 | 131212332021202333132123 |
5 | 114032021432300131112 |
6 | 1140542521152323551 |
7 | 36300121132042045 |
oct | 3546761142773633 |
9 | 562061221775654 |
10 | 130221421098907 |
11 | 3854665a388056 |
12 | 1273194a5435b7 |
13 | 5787a9a8070c8 |
14 | 2422a711aaa95 |
15 | 100c5583ea0a7 |
hex | 766f898bf79b |
130221421098907 has 2 divisors, whose sum is σ = 130221421098908. Its totient is φ = 130221421098906.
The previous prime is 130221421098877. The next prime is 130221421098919. The reversal of 130221421098907 is 709890124122031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130221421098907 is a prime.
It is a super-2 number, since 2×1302214210989072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130221421098407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110710549453 + 65110710549454.
It is an arithmetic number, because the mean of its divisors is an integer number (65110710549454).
Almost surely, 2130221421098907 is an apocalyptic number.
130221421098907 is a deficient number, since it is larger than the sum of its proper divisors (1).
130221421098907 is an equidigital number, since it uses as much as digits as its factorization.
130221421098907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 435456, while the sum is 49.
The spelling of 130221421098907 in words is "one hundred thirty trillion, two hundred twenty-one billion, four hundred twenty-one million, ninety-eight thousand, nine hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •