Base | Representation |
---|---|
bin | 11101100110111110001001… |
… | …100011000000000000001011 |
3 | 122002002001020201212122200211 |
4 | 131212332021203000000023 |
5 | 114032021432300213232 |
6 | 1140542521152341551 |
7 | 36300121132051252 |
oct | 3546761143000013 |
9 | 562061221778624 |
10 | 130221421101067 |
11 | 3854665a38973a |
12 | 1273194a5448b7 |
13 | 5787a9a80809a |
14 | 2422a711ab799 |
15 | 100c5583eaa47 |
hex | 766f898c000b |
130221421101067 has 2 divisors, whose sum is σ = 130221421101068. Its totient is φ = 130221421101066.
The previous prime is 130221421100963. The next prime is 130221421101119. The reversal of 130221421101067 is 760101124122031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130221421101067 - 227 = 130221286883339 is a prime.
It is not a weakly prime, because it can be changed into another prime (130221421141067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65110710550533 + 65110710550534.
It is an arithmetic number, because the mean of its divisors is an integer number (65110710550534).
Almost surely, 2130221421101067 is an apocalyptic number.
130221421101067 is a deficient number, since it is larger than the sum of its proper divisors (1).
130221421101067 is an equidigital number, since it uses as much as digits as its factorization.
130221421101067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 130221421101067 its reverse (760101124122031), we get a palindrome (890322545223098).
The spelling of 130221421101067 in words is "one hundred thirty trillion, two hundred twenty-one billion, four hundred twenty-one million, one hundred one thousand, sixty-seven".
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