Base | Representation |
---|---|
bin | 1011110101111111100000… |
… | …1110000110101111111001 |
3 | 1201002220121020010202110211 |
4 | 2331133320032012233321 |
5 | 3201323441320241101 |
6 | 43410153144511121 |
7 | 2512552340253121 |
oct | 275377016065771 |
9 | 51086536122424 |
10 | 13022210321401 |
11 | 4170763268a16 |
12 | 156395ba7b4a1 |
13 | 735cb2269628 |
14 | 3303c7ab3c81 |
15 | 178b0e4acc51 |
hex | bd7f8386bf9 |
13022210321401 has 2 divisors, whose sum is σ = 13022210321402. Its totient is φ = 13022210321400.
The previous prime is 13022210321383. The next prime is 13022210321413. The reversal of 13022210321401 is 10412301222031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11172814315776 + 1849396005625 = 3342576^2 + 1359925^2 .
It is a cyclic number.
It is not a de Polignac number, because 13022210321401 - 27 = 13022210321273 is a prime.
It is not a weakly prime, because it can be changed into another prime (13022210321431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511105160700 + 6511105160701.
It is an arithmetic number, because the mean of its divisors is an integer number (6511105160701).
Almost surely, 213022210321401 is an apocalyptic number.
It is an amenable number.
13022210321401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022210321401 is an equidigital number, since it uses as much as digits as its factorization.
13022210321401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13022210321401 its reverse (10412301222031), we get a palindrome (23434511543432).
The spelling of 13022210321401 in words is "thirteen trillion, twenty-two billion, two hundred ten million, three hundred twenty-one thousand, four hundred one".
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