1302221131121 has 2 divisors, whose sum is σ = 1302221131122. Its totient is φ = 1302221131120.

The previous prime is 1302221131067. The next prime is 1302221131129. The reversal of 1302221131121 is 1211311222031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1297013488225 + 5207642896 = 1138865^2 + 72164^2 .

It is an emirp because it is prime and its reverse (1211311222031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1302221131121 - 2²² = 1302216936817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1302221131093 and 1302221131102.

It is not a weakly prime, because it can be changed into another prime (1302221131129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651110565560 + 651110565561.

It is an arithmetic number, because the mean of its divisors is an integer number (651110565561).

Almost surely, 2^{1302221131121} is an apocalyptic number.

It is an amenable number.

1302221131121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302221131121 is an equidigital number, since it uses as much as digits as its factorization.

1302221131121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1302221131121 its reverse (1211311222031), we get a palindrome (2513532353152).

The spelling of 1302221131121 in words is "one trillion, three hundred two billion, two hundred twenty-one million, one hundred thirty-one thousand, one hundred twenty-one".