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1302222012041 is a prime number
BaseRepresentation
bin10010111100110010011…
…110101111111010001001
311121111021002110100201102
4102330302132233322021
5132313422313341131
62434122121031145
7163040163316526
oct22746236577211
94544232410642
101302222012041
114622a6416785
121904676254b5
1395a50564c72
144705671614d
1523d1903e1cb
hex12f327afe89

1302222012041 has 2 divisors, whose sum is σ = 1302222012042. Its totient is φ = 1302222012040.

The previous prime is 1302222012017. The next prime is 1302222012053. The reversal of 1302222012041 is 1402102222031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 937169205625 + 365052806416 = 968075^2 + 604196^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1302222012041 is a prime.

It is a super-2 number, since 2×13022220120412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1302222012071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651111006020 + 651111006021.

It is an arithmetic number, because the mean of its divisors is an integer number (651111006021).

Almost surely, 21302222012041 is an apocalyptic number.

It is an amenable number.

1302222012041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302222012041 is an equidigital number, since it uses as much as digits as its factorization.

1302222012041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1302222012041 its reverse (1402102222031), we get a palindrome (2704324234072).

The spelling of 1302222012041 in words is "one trillion, three hundred two billion, two hundred twenty-two million, twelve thousand, forty-one".