Base | Representation |
---|---|
bin | 10010111100110010011… |
… | …110101111111010001001 |
3 | 11121111021002110100201102 |
4 | 102330302132233322021 |
5 | 132313422313341131 |
6 | 2434122121031145 |
7 | 163040163316526 |
oct | 22746236577211 |
9 | 4544232410642 |
10 | 1302222012041 |
11 | 4622a6416785 |
12 | 1904676254b5 |
13 | 95a50564c72 |
14 | 4705671614d |
15 | 23d1903e1cb |
hex | 12f327afe89 |
1302222012041 has 2 divisors, whose sum is σ = 1302222012042. Its totient is φ = 1302222012040.
The previous prime is 1302222012017. The next prime is 1302222012053. The reversal of 1302222012041 is 1402102222031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 937169205625 + 365052806416 = 968075^2 + 604196^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302222012041 is a prime.
It is a super-2 number, since 2×13022220120412 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1302222012071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651111006020 + 651111006021.
It is an arithmetic number, because the mean of its divisors is an integer number (651111006021).
Almost surely, 21302222012041 is an apocalyptic number.
It is an amenable number.
1302222012041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302222012041 is an equidigital number, since it uses as much as digits as its factorization.
1302222012041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1302222012041 its reverse (1402102222031), we get a palindrome (2704324234072).
The spelling of 1302222012041 in words is "one trillion, three hundred two billion, two hundred twenty-two million, twelve thousand, forty-one".
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