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130230010223219 is a prime number
BaseRepresentation
bin11101100111000110001001…
…011111111001101001110011
3122002002212102022211021021002
4131213012021133321221303
5114032142030104120334
61140550501335152215
736300544025303564
oct3547061137715163
9562085368737232
10130230010223219
113854a2677552a5
1212733546b1566b
13578883910879a
142423247bca16b
15100c8ac4b5b7e
hex7671897f9a73

130230010223219 has 2 divisors, whose sum is σ = 130230010223220. Its totient is φ = 130230010223218.

The previous prime is 130230010223149. The next prime is 130230010223249. The reversal of 130230010223219 is 912322010032031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130230010223219 - 240 = 129130498595443 is a prime.

It is a super-2 number, since 2×1302300102232192 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130230010223191 and 130230010223200.

It is not a weakly prime, because it can be changed into another prime (130230010223249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115005111609 + 65115005111610.

It is an arithmetic number, because the mean of its divisors is an integer number (65115005111610).

Almost surely, 2130230010223219 is an apocalyptic number.

130230010223219 is a deficient number, since it is larger than the sum of its proper divisors (1).

130230010223219 is an equidigital number, since it uses as much as digits as its factorization.

130230010223219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 130230010223219 in words is "one hundred thirty trillion, two hundred thirty billion, ten million, two hundred twenty-three thousand, two hundred nineteen".