Base | Representation |
---|---|
bin | 1011110110000010011101… |
… | …0111001011101011000101 |
3 | 1201002222122100101002010200 |
4 | 2331200213113023223011 |
5 | 3201332101303330041 |
6 | 43410403440441113 |
7 | 2512611053003136 |
oct | 275404727135305 |
9 | 51088570332120 |
10 | 13023001230021 |
11 | 417102975a302 |
12 | 1563b40919199 |
13 | 7360aa0883b3 |
14 | 330460b53c8d |
15 | 178b58b3b1b6 |
hex | bd8275cbac5 |
13023001230021 has 24 divisors (see below), whose sum is σ = 18844924901400. Its totient is φ = 8666346110976.
The previous prime is 13023001230017. The next prime is 13023001230047. The reversal of 13023001230021 is 12003210032031.
13023001230021 is a `hidden beast` number, since 1 + 30 + 2 + 300 + 12 + 300 + 21 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 7309534068225 + 5713467161796 = 2703615^2 + 2390286^2 .
It is not a de Polignac number, because 13023001230021 - 22 = 13023001230017 is a prime.
It is a super-2 number, since 2×130230012300212 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13023001229976 and 13023001230003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13023001240021) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 81185131 + ... + 81345383.
It is an arithmetic number, because the mean of its divisors is an integer number (785205204225).
Almost surely, 213023001230021 is an apocalyptic number.
It is an amenable number.
13023001230021 is a deficient number, since it is larger than the sum of its proper divisors (5821923671379).
13023001230021 is a wasteful number, since it uses less digits than its factorization.
13023001230021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 176485 (or 176482 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13023001230021 its reverse (12003210032031), we get a palindrome (25026211262052).
The spelling of 13023001230021 in words is "thirteen trillion, twenty-three billion, one million, two hundred thirty thousand, twenty-one".
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