Base | Representation |
---|---|
bin | 1011110110000010011101… |
… | …0111010101000000010011 |
3 | 1201002222122100110000120022 |
4 | 2331200213113111000103 |
5 | 3201332101311040433 |
6 | 43410403441334055 |
7 | 2512611053222441 |
oct | 275404727250023 |
9 | 51088570400508 |
10 | 13023001268243 |
11 | 4171029785a9a |
12 | 1563b4093732b |
13 | 7360aa09c905 |
14 | 330460b63b91 |
15 | 178b58b47698 |
hex | bd8275d5013 |
13023001268243 has 2 divisors, whose sum is σ = 13023001268244. Its totient is φ = 13023001268242.
The previous prime is 13023001268153. The next prime is 13023001268257. The reversal of 13023001268243 is 34286210032031.
It is a strong prime.
It is an emirp because it is prime and its reverse (34286210032031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13023001268243 - 216 = 13023001202707 is a prime.
It is not a weakly prime, because it can be changed into another prime (13023001268293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511500634121 + 6511500634122.
It is an arithmetic number, because the mean of its divisors is an integer number (6511500634122).
Almost surely, 213023001268243 is an apocalyptic number.
13023001268243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023001268243 is an equidigital number, since it uses as much as digits as its factorization.
13023001268243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 13023001268243 in words is "thirteen trillion, twenty-three billion, one million, two hundred sixty-eight thousand, two hundred forty-three".
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