Base | Representation |
---|---|
bin | 11101100111000110011010… |
… | …110110010111000000111011 |
3 | 122002002220011121120200112102 |
4 | 131213012122312113000323 |
5 | 114032143124114321243 |
6 | 1140550550254334015 |
7 | 36300554161515125 |
oct | 3547063266270073 |
9 | 562086147520472 |
10 | 130230301323323 |
11 | 3854a3a70000a3 |
12 | 127336084ba30b |
13 | 578888450b676 |
14 | 2423274724215 |
15 | 100c8c7d179b8 |
hex | 76719ad9703b |
130230301323323 has 2 divisors, whose sum is σ = 130230301323324. Its totient is φ = 130230301323322.
The previous prime is 130230301323307. The next prime is 130230301323347. The reversal of 130230301323323 is 323323103032031.
It is a weak prime.
It is an emirp because it is prime and its reverse (323323103032031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130230301323323 - 24 = 130230301323307 is a prime.
It is not a weakly prime, because it can be changed into another prime (130230301323223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115150661661 + 65115150661662.
It is an arithmetic number, because the mean of its divisors is an integer number (65115150661662).
Almost surely, 2130230301323323 is an apocalyptic number.
130230301323323 is a deficient number, since it is larger than the sum of its proper divisors (1).
130230301323323 is an equidigital number, since it uses as much as digits as its factorization.
130230301323323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 130230301323323 its reverse (323323103032031), we get a palindrome (453553404355354).
The spelling of 130230301323323 in words is "one hundred thirty trillion, two hundred thirty billion, three hundred one million, three hundred twenty-three thousand, three hundred twenty-three".
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