Base | Representation |
---|---|
bin | 10010111100110111110… |
… | …110011111011010011011 |
3 | 11121111111101000102100201 |
4 | 102330313312133122123 |
5 | 132314113400401021 |
6 | 2434135100243031 |
7 | 163042336251025 |
oct | 22746766373233 |
9 | 4544441012321 |
10 | 1302312122011 |
11 | 46234227272a |
12 | 190491840477 |
13 | 95a66124c84 |
14 | 47064691015 |
15 | 23d21ddd591 |
hex | 12f37d9f69b |
1302312122011 has 2 divisors, whose sum is σ = 1302312122012. Its totient is φ = 1302312122010.
The previous prime is 1302312121961. The next prime is 1302312122039. The reversal of 1302312122011 is 1102212132031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1302312122011 - 29 = 1302312121499 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1302312122011.
It is not a weakly prime, because it can be changed into another prime (1302312122411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651156061005 + 651156061006.
It is an arithmetic number, because the mean of its divisors is an integer number (651156061006).
Almost surely, 21302312122011 is an apocalyptic number.
1302312122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302312122011 is an equidigital number, since it uses as much as digits as its factorization.
1302312122011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1302312122011 its reverse (1102212132031), we get a palindrome (2404524254042).
The spelling of 1302312122011 in words is "one trillion, three hundred two billion, three hundred twelve million, one hundred twenty-two thousand, eleven".
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