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130231324223041 is a prime number
BaseRepresentation
bin11101100111000111010111…
…110100011010011001000001
3122002002222210220100101011011
4131213013113310122121001
5114032202223000114131
61140551235554520521
736300621422153056
oct3547072764323101
9562088726311134
10130231324223041
113854a881444868
1212733852b96141
1357889b8405a82
14242333051302d
15100c937a1e0b1
hex7671d7d1a641

130231324223041 has 2 divisors, whose sum is σ = 130231324223042. Its totient is φ = 130231324223040.

The previous prime is 130231324223029. The next prime is 130231324223051. The reversal of 130231324223041 is 140322423132031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129999424189441 + 231900033600 = 11401729^2 + 481560^2 .

It is a cyclic number.

It is not a de Polignac number, because 130231324223041 - 215 = 130231324190273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130231324222994 and 130231324223012.

It is not a weakly prime, because it can be changed into another prime (130231324223051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65115662111520 + 65115662111521.

It is an arithmetic number, because the mean of its divisors is an integer number (65115662111521).

Almost surely, 2130231324223041 is an apocalyptic number.

It is an amenable number.

130231324223041 is a deficient number, since it is larger than the sum of its proper divisors (1).

130231324223041 is an equidigital number, since it uses as much as digits as its factorization.

130231324223041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 130231324223041 its reverse (140322423132031), we get a palindrome (270553747355072).

The spelling of 130231324223041 in words is "one hundred thirty trillion, two hundred thirty-one billion, three hundred twenty-four million, two hundred twenty-three thousand, forty-one".