Base | Representation |
---|---|
bin | 10010111100110111111… |
… | …011000110110111000001 |
3 | 11121111111110021220101002 |
4 | 102330313323012313001 |
5 | 132314114203112121 |
6 | 2434135142221345 |
7 | 163042352451122 |
oct | 22746773066701 |
9 | 4544443256332 |
10 | 1302313332161 |
11 | 462342a19956 |
12 | 190492124855 |
13 | 95a66459a3a |
14 | 470648c8049 |
15 | 23d2207be0b |
hex | 12f37ec6dc1 |
1302313332161 has 2 divisors, whose sum is σ = 1302313332162. Its totient is φ = 1302313332160.
The previous prime is 1302313332127. The next prime is 1302313332181. The reversal of 1302313332161 is 1612333132031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1215947290000 + 86366042161 = 1102700^2 + 293881^2 .
It is an emirp because it is prime and its reverse (1612333132031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302313332161 is a prime.
It is not a weakly prime, because it can be changed into another prime (1302313332181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651156666080 + 651156666081.
It is an arithmetic number, because the mean of its divisors is an integer number (651156666081).
Almost surely, 21302313332161 is an apocalyptic number.
It is an amenable number.
1302313332161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302313332161 is an equidigital number, since it uses as much as digits as its factorization.
1302313332161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 1302313332161 its reverse (1612333132031), we get a palindrome (2914646464192).
The spelling of 1302313332161 in words is "one trillion, three hundred two billion, three hundred thirteen million, three hundred thirty-two thousand, one hundred sixty-one".
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