Base | Representation |
---|---|
bin | 11101100111001001001110… |
… | …010111110101011001101011 |
3 | 122002010011221111222220022201 |
4 | 131213021032113311121223 |
5 | 114032220311141021303 |
6 | 1140552205210001031 |
7 | 36301021623310444 |
oct | 3547111627653153 |
9 | 562104844886281 |
10 | 130233313220203 |
11 | 38550702156876 |
12 | 12734109116177 |
13 | 5788c444c9c7b |
14 | 242347c7462cb |
15 | 100ca0245b81d |
hex | 76724e5f566b |
130233313220203 has 2 divisors, whose sum is σ = 130233313220204. Its totient is φ = 130233313220202.
The previous prime is 130233313220167. The next prime is 130233313220221. The reversal of 130233313220203 is 302022313332031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130233313220203 - 233 = 130224723285611 is a prime.
It is a super-2 number, since 2×1302333132202032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130233313220293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65116656610101 + 65116656610102.
It is an arithmetic number, because the mean of its divisors is an integer number (65116656610102).
Almost surely, 2130233313220203 is an apocalyptic number.
130233313220203 is a deficient number, since it is larger than the sum of its proper divisors (1).
130233313220203 is an equidigital number, since it uses as much as digits as its factorization.
130233313220203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 130233313220203 its reverse (302022313332031), we get a palindrome (432255626552234).
The spelling of 130233313220203 in words is "one hundred thirty trillion, two hundred thirty-three billion, three hundred thirteen million, two hundred twenty thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •