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13023403 = 33133931
BaseRepresentation
bin110001101011…
…100010101011
3220111122202021
4301223202223
511313222103
61143045311
7215461051
oct61534253
926448667
1013023403
117395748
124440837
13290ca73
141a301d1
151223bbd
hexc6b8ab

13023403 has 4 divisors (see below), whose sum is σ = 13030648. Its totient is φ = 13016160.

The previous prime is 13023391. The next prime is 13023421. The reversal of 13023403 is 30432031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13023403 - 217 = 12892331 is a prime.

It is a Duffinian number.

It is a plaindrome in base 15.

It is not an unprimeable number, because it can be changed into a prime (13023433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1348 + ... + 5278.

It is an arithmetic number, because the mean of its divisors is an integer number (3257662).

Almost surely, 213023403 is an apocalyptic number.

13023403 is a deficient number, since it is larger than the sum of its proper divisors (7245).

13023403 is an equidigital number, since it uses as much as digits as its factorization.

13023403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7244.

The product of its (nonzero) digits is 216, while the sum is 16.

The square root of 13023403 is about 3608.7952283276. The cubic root of 13023403 is about 235.2744823554.

Adding to 13023403 its reverse (30432031), we get a palindrome (43455434).

The spelling of 13023403 in words is "thirteen million, twenty-three thousand, four hundred three".

Divisors: 1 3313 3931 13023403