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13023433 is a prime number
BaseRepresentation
bin110001101011…
…100011001001
3220111122210101
4301223203021
511313222213
61143045401
7215461123
oct61534311
926448711
1013023433
117395775
124440861
13290ca97
141a30213
151223bdd
hexc6b8c9

13023433 has 2 divisors, whose sum is σ = 13023434. Its totient is φ = 13023432.

The previous prime is 13023427. The next prime is 13023457. The reversal of 13023433 is 33432031.

13023433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11614464 + 1408969 = 3408^2 + 1187^2 .

It is a cyclic number.

It is not a de Polignac number, because 13023433 - 213 = 13015241 is a prime.

It is a plaindrome in base 15.

It is a self number, because there is not a number n which added to its sum of digits gives 13023433.

It is not a weakly prime, because it can be changed into another prime (13023133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511716 + 6511717.

It is an arithmetic number, because the mean of its divisors is an integer number (6511717).

Almost surely, 213023433 is an apocalyptic number.

It is an amenable number.

13023433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023433 is an equidigital number, since it uses as much as digits as its factorization.

13023433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 19.

The square root of 13023433 is about 3608.7993848370. The cubic root of 13023433 is about 235.2746630104.

Adding to 13023433 its reverse (33432031), we get a palindrome (46455464).

It can be divided in two parts, 13023 and 433, that added together give a square (13456 = 1162).

The spelling of 13023433 in words is "thirteen million, twenty-three thousand, four hundred thirty-three".