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130240344122234 = 265120172061117
BaseRepresentation
bin11101100111001111110001…
…011100100110001101111010
3122002010212002111212201201122
4131213033301130212031322
5114032324211043402414
61140555331010345242
736301361066063213
oct3547176134461572
9562125074781648
10130240344122234
113855368a997605
121273554b88b222
1357897c5032628
14242394842840a
15100ccb482bb8e
hex7673f172637a

130240344122234 has 4 divisors (see below), whose sum is σ = 195360516183354. Its totient is φ = 65120172061116.

The previous prime is 130240344122227. The next prime is 130240344122327. The reversal of 130240344122234 is 432221443042031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 120730540185025 + 9509803937209 = 10987745^2 + 3083797^2 .

It is a junction number, because it is equal to n+sod(n) for n = 130240344122194 and 130240344122203.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32560086030557 + ... + 32560086030560.

Almost surely, 2130240344122234 is an apocalyptic number.

130240344122234 is a deficient number, since it is larger than the sum of its proper divisors (65120172061120).

130240344122234 is an equidigital number, since it uses as much as digits as its factorization.

130240344122234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65120172061119.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 130240344122234 its reverse (432221443042031), we get a palindrome (562461787164265).

The spelling of 130240344122234 in words is "one hundred thirty trillion, two hundred forty billion, three hundred forty-four million, one hundred twenty-two thousand, two hundred thirty-four".

Divisors: 1 2 65120172061117 130240344122234