Base | Representation |
---|---|
bin | 1111100001101… |
… | …01001001010011 |
3 | 100002001221012201 |
4 | 13300311021103 |
5 | 231320203412 |
6 | 20531304031 |
7 | 3141013453 |
oct | 760651123 |
9 | 302057181 |
10 | 130241107 |
11 | 67577087 |
12 | 3774b017 |
13 | 20ca1459 |
14 | 13423d63 |
15 | b679e57 |
hex | 7c35253 |
130241107 has 2 divisors, whose sum is σ = 130241108. Its totient is φ = 130241106.
The previous prime is 130241081. The next prime is 130241119. The reversal of 130241107 is 701142031.
It is a strong prime.
It is an emirp because it is prime and its reverse (701142031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130241107 is a prime.
It is not a weakly prime, because it can be changed into another prime (130241197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65120553 + 65120554.
It is an arithmetic number, because the mean of its divisors is an integer number (65120554).
Almost surely, 2130241107 is an apocalyptic number.
130241107 is a deficient number, since it is larger than the sum of its proper divisors (1).
130241107 is an equidigital number, since it uses as much as digits as its factorization.
130241107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 19.
The square root of 130241107 is about 11412.3225944590. The cubic root of 130241107 is about 506.8926877567.
Adding to 130241107 its reverse (701142031), we get a palindrome (831383138).
The spelling of 130241107 in words is "one hundred thirty million, two hundred forty-one thousand, one hundred seven".
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