Base | Representation |
---|---|
bin | 11101100111010000100100… |
… | …100101001001110111101010 |
3 | 122002010221022022010121111102 |
4 | 131213100210211021313222 |
5 | 114032332440203102214 |
6 | 1140555552054001402 |
7 | 36301421254000454 |
oct | 3547204445116752 |
9 | 562127268117442 |
10 | 130241202003434 |
11 | 38553a90171435 |
12 | 1273574b046262 |
13 | 578990099cc42 |
14 | 24239ca33d2d4 |
15 | 100cd14cd8bde |
hex | 767424949dea |
130241202003434 has 4 divisors (see below), whose sum is σ = 195361803005154. Its totient is φ = 65120601001716.
The previous prime is 130241202003431. The next prime is 130241202003469. The reversal of 130241202003434 is 434300202142031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 108944850652225 + 21296351351209 = 10437665^2 + 4614797^2 .
It is a junction number, because it is equal to n+sod(n) for n = 130241202003397 and 130241202003406.
It is not an unprimeable number, because it can be changed into a prime (130241202003431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32560300500857 + ... + 32560300500860.
Almost surely, 2130241202003434 is an apocalyptic number.
130241202003434 is a deficient number, since it is larger than the sum of its proper divisors (65120601001720).
130241202003434 is an equidigital number, since it uses as much as digits as its factorization.
130241202003434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65120601001719.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 130241202003434 its reverse (434300202142031), we get a palindrome (564541404145465).
The spelling of 130241202003434 in words is "one hundred thirty trillion, two hundred forty-one billion, two hundred two million, three thousand, four hundred thirty-four".
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