Base | Representation |
---|---|
bin | 110001010111111100110010… |
… | …1010001100100100101001111 |
3 | 2002221201200201210221111001002 |
4 | 1202233321211101210211033 |
5 | 423411033303222021111 |
6 | 4135402431502010515 |
7 | 160323103605415601 |
oct | 14257714521444517 |
9 | 2087650653844032 |
10 | 434300202142031 |
11 | 116421754a20945 |
12 | 40862356b76a3b |
13 | 1584444443b5a4 |
14 | 7936355c55171 |
15 | 35322291a063b |
hex | 18afe6546494f |
434300202142031 has 2 divisors, whose sum is σ = 434300202142032. Its totient is φ = 434300202142030.
The previous prime is 434300202142019. The next prime is 434300202142061. The reversal of 434300202142031 is 130241202003434.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 434300202142031 - 210 = 434300202141007 is a prime.
It is a super-2 number, since 2×4343002021420312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 434300202141985 and 434300202142003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434300202142061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217150101071015 + 217150101071016.
It is an arithmetic number, because the mean of its divisors is an integer number (217150101071016).
Almost surely, 2434300202142031 is an apocalyptic number.
434300202142031 is a deficient number, since it is larger than the sum of its proper divisors (1).
434300202142031 is an equidigital number, since it uses as much as digits as its factorization.
434300202142031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 434300202142031 its reverse (130241202003434), we get a palindrome (564541404145465).
The spelling of 434300202142031 in words is "four hundred thirty-four trillion, three hundred billion, two hundred two million, one hundred forty-two thousand, thirty-one".
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