Base | Representation |
---|---|
bin | 10010111100111110010… |
… | …110010000110101110111 |
3 | 11121111202222002210120121 |
4 | 102330332112100311313 |
5 | 132314324301123411 |
6 | 2434153552312411 |
7 | 163045131544426 |
oct | 22747626206567 |
9 | 4544688083517 |
10 | 1302421114231 |
11 | 462398846146 |
12 | 190502242707 |
13 | 95a82896703 |
14 | 47074d432bd |
15 | 23d2b76c571 |
hex | 12f3e590d77 |
1302421114231 has 16 divisors (see below), whose sum is σ = 1320443182080. Its totient is φ = 1284561036640.
The previous prime is 1302421114207. The next prime is 1302421114237. The reversal of 1302421114231 is 1324111242031.
It is a cyclic number.
It is not a de Polignac number, because 1302421114231 - 221 = 1302419017079 is a prime.
It is a super-2 number, since 2×13024211142312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1302421114196 and 1302421114205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1302421114237) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10814376 + ... + 10934146.
It is an arithmetic number, because the mean of its divisors is an integer number (82527698880).
Almost surely, 21302421114231 is an apocalyptic number.
1302421114231 is a deficient number, since it is larger than the sum of its proper divisors (18022067849).
1302421114231 is a wasteful number, since it uses less digits than its factorization.
1302421114231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120446.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1302421114231 its reverse (1324111242031), we get a palindrome (2626532356262).
The spelling of 1302421114231 in words is "one trillion, three hundred two billion, four hundred twenty-one million, one hundred fourteen thousand, two hundred thirty-one".
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