Base | Representation |
---|---|
bin | 10010111100111111001… |
… | …000010101110111010001 |
3 | 11121111210212210202111022 |
4 | 102330333020111313101 |
5 | 132314341131221001 |
6 | 2434155141525225 |
7 | 163045351252004 |
oct | 22747710256721 |
9 | 4544725722438 |
10 | 1302434242001 |
11 | 4623a51a2242 |
12 | 190506713815 |
13 | 95a85511b19 |
14 | 4707699d53b |
15 | 23d2c9b211b |
hex | 12f3f215dd1 |
1302434242001 has 2 divisors, whose sum is σ = 1302434242002. Its totient is φ = 1302434242000.
The previous prime is 1302434241991. The next prime is 1302434242009. The reversal of 1302434242001 is 1002424342031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 872727771601 + 429706470400 = 934199^2 + 655520^2 .
It is a cyclic number.
It is not a de Polignac number, because 1302434242001 - 230 = 1301360500177 is a prime.
It is not a weakly prime, because it can be changed into another prime (1302434242009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651217121000 + 651217121001.
It is an arithmetic number, because the mean of its divisors is an integer number (651217121001).
Almost surely, 21302434242001 is an apocalyptic number.
It is an amenable number.
1302434242001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302434242001 is an equidigital number, since it uses as much as digits as its factorization.
1302434242001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 1302434242001 its reverse (1002424342031), we get a palindrome (2304858584032).
The spelling of 1302434242001 in words is "one trillion, three hundred two billion, four hundred thirty-four million, two hundred forty-two thousand, one".
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