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130244410141 = 3714627240659
BaseRepresentation
bin111100101001100101…
…0111111101100011101
3110110011221211120022021
41321103022333230131
54113220032111031
6135500005420141
712260402135236
oct1712312775435
9413157746267
10130244410141
115026663508a
12212aa70a651
13c38870ab11
146437b2c08d
1535c4541511
hex1e532bfb1d

130244410141 has 8 divisors (see below), whose sum is σ = 133774230240. Its totient is φ = 126715100688.

The previous prime is 130244410123. The next prime is 130244410157. The reversal of 130244410141 is 141014442031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130244410141 - 213 = 130244401949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130244410441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 420870 + ... + 661528.

It is an arithmetic number, because the mean of its divisors is an integer number (16721778780).

Almost surely, 2130244410141 is an apocalyptic number.

It is an amenable number.

130244410141 is a deficient number, since it is larger than the sum of its proper divisors (3529820099).

130244410141 is a wasteful number, since it uses less digits than its factorization.

130244410141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 255323.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 130244410141 its reverse (141014442031), we get a palindrome (271258852172).

The spelling of 130244410141 in words is "one hundred thirty billion, two hundred forty-four million, four hundred ten thousand, one hundred forty-one".

Divisors: 1 37 14627 240659 541199 8904383 3520119193 130244410141