Base | Representation |
---|---|
bin | 1111100001101… |
… | …10001100011011 |
3 | 100002002011002211 |
4 | 13300312030123 |
5 | 231320323103 |
6 | 20531335551 |
7 | 3141032131 |
oct | 760661433 |
9 | 302064084 |
10 | 130245403 |
11 | 6757a332 |
12 | 377515b7 |
13 | 20ca33b2 |
14 | 13425751 |
15 | b67b36d |
hex | 7c3631b |
130245403 has 2 divisors, whose sum is σ = 130245404. Its totient is φ = 130245402.
The previous prime is 130245377. The next prime is 130245407. The reversal of 130245403 is 304542031.
It is a strong prime.
It is an emirp because it is prime and its reverse (304542031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130245403 - 25 = 130245371 is a prime.
It is not a weakly prime, because it can be changed into another prime (130245407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65122701 + 65122702.
It is an arithmetic number, because the mean of its divisors is an integer number (65122702).
Almost surely, 2130245403 is an apocalyptic number.
130245403 is a deficient number, since it is larger than the sum of its proper divisors (1).
130245403 is an equidigital number, since it uses as much as digits as its factorization.
130245403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 22.
The square root of 130245403 is about 11412.5108105097. The cubic root of 130245403 is about 506.8982609768.
Adding to 130245403 its reverse (304542031), we get a palindrome (434787434).
The spelling of 130245403 in words is "one hundred thirty million, two hundred forty-five thousand, four hundred three".
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