Base | Representation |
---|---|
bin | 11000010000101100… |
… | …11011110001110001 |
3 | 1020121201211120210012 |
4 | 30020112123301301 |
5 | 203133400004221 |
6 | 5552242544305 |
7 | 640525451366 |
oct | 141026336161 |
9 | 36551746705 |
10 | 13025000561 |
11 | 5584300781 |
12 | 2636068095 |
13 | 12c7616231 |
14 | 8b7bd646d |
15 | 51373e65b |
hex | 30859bc71 |
13025000561 has 2 divisors, whose sum is σ = 13025000562. Its totient is φ = 13025000560.
The previous prime is 13025000509. The next prime is 13025000567. The reversal of 13025000561 is 16500052031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9169211536 + 3855789025 = 95756^2 + 62095^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13025000561 is a prime.
It is a super-2 number, since 2×130250005612 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13025000567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6512500280 + 6512500281.
It is an arithmetic number, because the mean of its divisors is an integer number (6512500281).
Almost surely, 213025000561 is an apocalyptic number.
It is an amenable number.
13025000561 is a deficient number, since it is larger than the sum of its proper divisors (1).
13025000561 is an equidigital number, since it uses as much as digits as its factorization.
13025000561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 13025000561 its reverse (16500052031), we get a palindrome (29525052592).
The spelling of 13025000561 in words is "thirteen billion, twenty-five million, five hundred sixty-one", and thus it is an aban number.
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