Base | Representation |
---|---|
bin | 111100101010000000… |
… | …0001010111111000001 |
3 | 110110012221001210012222 |
4 | 1321110000022333001 |
5 | 4113232114200032 |
6 | 135501224300425 |
7 | 12260631464255 |
oct | 1712400127701 |
9 | 413187053188 |
10 | 130258350017 |
11 | 50273496344 |
12 | 212b3311715 |
13 | c38b57ba73 |
14 | 643991a265 |
15 | 35c5896a12 |
hex | 1e5400afc1 |
130258350017 has 2 divisors, whose sum is σ = 130258350018. Its totient is φ = 130258350016.
The previous prime is 130258349987. The next prime is 130258350031. The reversal of 130258350017 is 710053852031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91339346176 + 38919003841 = 302224^2 + 197279^2 .
It is an emirp because it is prime and its reverse (710053852031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130258350017 - 218 = 130258087873 is a prime.
It is not a weakly prime, because it can be changed into another prime (130258350037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65129175008 + 65129175009.
It is an arithmetic number, because the mean of its divisors is an integer number (65129175009).
Almost surely, 2130258350017 is an apocalyptic number.
It is an amenable number.
130258350017 is a deficient number, since it is larger than the sum of its proper divisors (1).
130258350017 is an equidigital number, since it uses as much as digits as its factorization.
130258350017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 35.
The spelling of 130258350017 in words is "one hundred thirty billion, two hundred fifty-eight million, three hundred fifty thousand, seventeen".
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