Base | Representation |
---|---|
bin | 11101100111100111001110… |
… | …001010101000000110011010 |
3 | 122002020021002012112002012112 |
4 | 131213213032022220012122 |
5 | 114033232242113400240 |
6 | 1141015053224112322 |
7 | 36303242033445260 |
oct | 3547471612500632 |
9 | 562207065462175 |
10 | 130265522012570 |
11 | 3856333018523a |
12 | 1273a3b79056a2 |
13 | 578bca83816a9 |
14 | 2424c5627a430 |
15 | 100d789e3c665 |
hex | 7679ce2a819a |
130265522012570 has 16 divisors (see below), whose sum is σ = 267974788140288. Its totient is φ = 44662464690000.
The previous prime is 130265522012471. The next prime is 130265522012603. The reversal of 130265522012570 is 75210225562031.
130265522012570 is digitally balanced in base 8, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 930468014306 + ... + 930468014445.
It is an arithmetic number, because the mean of its divisors is an integer number (16748424258768).
Almost surely, 2130265522012570 is an apocalyptic number.
130265522012570 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130265522012570 is an abundant number, since it is smaller than the sum of its proper divisors (137709266127718).
130265522012570 is a wasteful number, since it uses less digits than its factorization.
130265522012570 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1860936028765.
The product of its (nonzero) digits is 252000, while the sum is 41.
The spelling of 130265522012570 in words is "one hundred thirty trillion, two hundred sixty-five billion, five hundred twenty-two million, twelve thousand, five hundred seventy".
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