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13030001001302 = 26515000500651
BaseRepresentation
bin1011110110011100100010…
…0101001100001101010110
31201010122201011200022011212
42331213020211030031112
53201440420224020202
643413522210101422
72513246400040445
oct275471045141526
951118634608155
1013030001001302
114173aa096804a
121565374b7a872
137369543111ac
14330926650d5c
15178e1840c652
hexbd9c894c356

13030001001302 has 4 divisors (see below), whose sum is σ = 19545001501956. Its totient is φ = 6515000500650.

The previous prime is 13030001001301. The next prime is 13030001001331. The reversal of 13030001001302 is 20310010003031.

13030001001302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×130300010013022 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13030001001301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3257500250324 + ... + 3257500250327.

It is an arithmetic number, because the mean of its divisors is an integer number (4886250375489).

Almost surely, 213030001001302 is an apocalyptic number.

13030001001302 is a deficient number, since it is larger than the sum of its proper divisors (6515000500654).

13030001001302 is an equidigital number, since it uses as much as digits as its factorization.

13030001001302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6515000500653.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13030001001302 its reverse (20310010003031), we get a palindrome (33340011004333).

The spelling of 13030001001302 in words is "thirteen trillion, thirty billion, one million, one thousand, three hundred two".

Divisors: 1 2 6515000500651 13030001001302