Base | Representation |
---|---|
bin | 11101101000001000010110… |
… | …110101101101000100001011 |
3 | 122002100122220202200001201112 |
4 | 131220020112311231010023 |
5 | 114034323123324044034 |
6 | 1141043255513240535 |
7 | 36305641516045352 |
oct | 3550102665550413 |
9 | 562318822601645 |
10 | 130301101003019 |
11 | 38577428634381 |
12 | 1274528710314b |
13 | 579245852616b |
14 | 242686d620999 |
15 | 100e66d73a7ce |
hex | 768216d6d10b |
130301101003019 has 2 divisors, whose sum is σ = 130301101003020. Its totient is φ = 130301101003018.
The previous prime is 130301101002997. The next prime is 130301101003039. The reversal of 130301101003019 is 910300101103031.
It is a strong prime.
It is an emirp because it is prime and its reverse (910300101103031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130301101003019 - 212 = 130301100998923 is a prime.
It is a super-2 number, since 2×1303011010030192 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130301101002985 and 130301101003003.
It is not a weakly prime, because it can be changed into another prime (130301101003039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65150550501509 + 65150550501510.
It is an arithmetic number, because the mean of its divisors is an integer number (65150550501510).
Almost surely, 2130301101003019 is an apocalyptic number.
130301101003019 is a deficient number, since it is larger than the sum of its proper divisors (1).
130301101003019 is an equidigital number, since it uses as much as digits as its factorization.
130301101003019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 23.
The spelling of 130301101003019 in words is "one hundred thirty trillion, three hundred one billion, one hundred one million, three thousand, nineteen".
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