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130301101003019 is a prime number
BaseRepresentation
bin11101101000001000010110…
…110101101101000100001011
3122002100122220202200001201112
4131220020112311231010023
5114034323123324044034
61141043255513240535
736305641516045352
oct3550102665550413
9562318822601645
10130301101003019
1138577428634381
121274528710314b
13579245852616b
14242686d620999
15100e66d73a7ce
hex768216d6d10b

130301101003019 has 2 divisors, whose sum is σ = 130301101003020. Its totient is φ = 130301101003018.

The previous prime is 130301101002997. The next prime is 130301101003039. The reversal of 130301101003019 is 910300101103031.

It is a strong prime.

It is an emirp because it is prime and its reverse (910300101103031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130301101003019 - 212 = 130301100998923 is a prime.

It is a super-2 number, since 2×1303011010030192 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130301101002985 and 130301101003003.

It is not a weakly prime, because it can be changed into another prime (130301101003039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65150550501509 + 65150550501510.

It is an arithmetic number, because the mean of its divisors is an integer number (65150550501510).

Almost surely, 2130301101003019 is an apocalyptic number.

130301101003019 is a deficient number, since it is larger than the sum of its proper divisors (1).

130301101003019 is an equidigital number, since it uses as much as digits as its factorization.

130301101003019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 130301101003019 in words is "one hundred thirty trillion, three hundred one billion, one hundred one million, three thousand, nineteen".