Base | Representation |
---|---|
bin | 10010111101100111011… |
… | …011010100001010110000 |
3 | 11121120112222221021210121 |
4 | 102331213123110022300 |
5 | 132322232214220212 |
6 | 2434350212140024 |
7 | 163101200554336 |
oct | 22754733241260 |
9 | 4546488837717 |
10 | 1303110304432 |
11 | 462711881a22 |
12 | 190675007614 |
13 | 95b625bc771 |
14 | 470dc6a5b56 |
15 | 23d6c006d07 |
hex | 12f676d42b0 |
1303110304432 has 80 divisors (see below), whose sum is σ = 2637180923904. Its totient is φ = 623076480000.
The previous prime is 1303110304421. The next prime is 1303110304453. The reversal of 1303110304432 is 2344030113031.
It is a junction number, because it is equal to n+sod(n) for n = 1303110304397 and 1303110304406.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21251257 + ... + 21312487.
Almost surely, 21303110304432 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1303110304432, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1318590461952).
1303110304432 is an abundant number, since it is smaller than the sum of its proper divisors (1334070619472).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1303110304432 is a wasteful number, since it uses less digits than its factorization.
1303110304432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61778 (or 61772 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1303110304432 its reverse (2344030113031), we get a palindrome (3647140417463).
The spelling of 1303110304432 in words is "one trillion, three hundred three billion, one hundred ten million, three hundred four thousand, four hundred thirty-two".
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