Base | Representation |
---|---|
bin | 11101101000010001110110… |
… | …110100000100110011001001 |
3 | 122002101122020121222212020011 |
4 | 131220101312310010303021 |
5 | 114040010021041421043 |
6 | 1141052104005231521 |
7 | 36306452343455314 |
oct | 3550216664046311 |
9 | 562348217885204 |
10 | 130311301123273 |
11 | 38580792303726 |
12 | 127472531025a1 |
13 | 57933c281058a |
14 | 242715a19797b |
15 | 100ea68e7859d |
hex | 768476d04cc9 |
130311301123273 has 2 divisors, whose sum is σ = 130311301123274. Its totient is φ = 130311301123272.
The previous prime is 130311301123099. The next prime is 130311301123309. The reversal of 130311301123273 is 372321103113031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89648079983289 + 40663221139984 = 9468267^2 + 6376772^2 .
It is a cyclic number.
It is not a de Polignac number, because 130311301123273 - 245 = 95126929034441 is a prime.
It is not a weakly prime, because it can be changed into another prime (130311301123373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65155650561636 + 65155650561637.
It is an arithmetic number, because the mean of its divisors is an integer number (65155650561637).
Almost surely, 2130311301123273 is an apocalyptic number.
It is an amenable number.
130311301123273 is a deficient number, since it is larger than the sum of its proper divisors (1).
130311301123273 is an equidigital number, since it uses as much as digits as its factorization.
130311301123273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 31.
The spelling of 130311301123273 in words is "one hundred thirty trillion, three hundred eleven billion, three hundred one million, one hundred twenty-three thousand, two hundred seventy-three".
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