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130311310937497 is a prime number
BaseRepresentation
bin11101101000010001110111…
…011001100000110110011001
3122002101122021022110110210221
4131220101313121200312121
5114040010031044444442
61141052104555440041
736306452523052234
oct3550216731406631
9562348238413727
10130311310937497
11385807978a7258
1212747256456021
1357933c4868701
14242715b5d041b
15100ea69c66467
hex768477660d99

130311310937497 has 2 divisors, whose sum is σ = 130311310937498. Its totient is φ = 130311310937496.

The previous prime is 130311310937473. The next prime is 130311310937503. The reversal of 130311310937497 is 794739013113031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98919315580761 + 31391995356736 = 9945819^2 + 5602856^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130311310937497 is a prime.

It is a super-2 number, since 2×1303113109374972 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130311310947497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65155655468748 + 65155655468749.

It is an arithmetic number, because the mean of its divisors is an integer number (65155655468749).

Almost surely, 2130311310937497 is an apocalyptic number.

It is an amenable number.

130311310937497 is a deficient number, since it is larger than the sum of its proper divisors (1).

130311310937497 is an equidigital number, since it uses as much as digits as its factorization.

130311310937497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1285956, while the sum is 52.

The spelling of 130311310937497 in words is "one hundred thirty trillion, three hundred eleven billion, three hundred ten million, nine hundred thirty-seven thousand, four hundred ninety-seven".