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13031203113307 is a prime number
BaseRepresentation
bin1011110110100001000000…
…1110111000100101011011
31201010202210221122220211201
42331220100032320211123
53202000400444111212
643414241351335031
72513321234603251
oct275502016704533
951122727586751
1013031203113307
114174558486645
12156564b681477
13736ab6394a82
143309dc1705d1
15178e88c13b57
hexbda103b895b

13031203113307 has 2 divisors, whose sum is σ = 13031203113308. Its totient is φ = 13031203113306.

The previous prime is 13031203113287. The next prime is 13031203113311. The reversal of 13031203113307 is 70331130213031.

13031203113307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (70331130213031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13031203113307 - 27 = 13031203113179 is a prime.

It is not a weakly prime, because it can be changed into another prime (13031203113337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515601556653 + 6515601556654.

It is an arithmetic number, because the mean of its divisors is an integer number (6515601556654).

Almost surely, 213031203113307 is an apocalyptic number.

13031203113307 is a deficient number, since it is larger than the sum of its proper divisors (1).

13031203113307 is an equidigital number, since it uses as much as digits as its factorization.

13031203113307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 28.

Adding to 13031203113307 its reverse (70331130213031), we get a palindrome (83362333326338).

The spelling of 13031203113307 in words is "thirteen trillion, thirty-one billion, two hundred three million, one hundred thirteen thousand, three hundred seven".