Base | Representation |
---|---|
bin | 11101101000010101010101… |
… | …110100010111110101010010 |
3 | 122002101222220101002112020012 |
4 | 131220111111310113311102 |
5 | 114040040201341123102 |
6 | 1141053523140314522 |
7 | 36306644144016545 |
oct | 3550252564276522 |
9 | 562358811075205 |
10 | 130315042520402 |
11 | 38582332218773 |
12 | 12747b180a2a42 |
13 | 579386a99992c |
14 | 24273d303285c |
15 | 100ebd766a752 |
hex | 768555d17d52 |
130315042520402 has 4 divisors (see below), whose sum is σ = 195472563780606. Its totient is φ = 65157521260200.
The previous prime is 130315042520401. The next prime is 130315042520437. The reversal of 130315042520402 is 204025240513031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 88842331235641 + 41472711284761 = 9425621^2 + 6439931^2 .
It is not an unprimeable number, because it can be changed into a prime (130315042520401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32578760630099 + ... + 32578760630102.
Almost surely, 2130315042520402 is an apocalyptic number.
130315042520402 is a deficient number, since it is larger than the sum of its proper divisors (65157521260204).
130315042520402 is an equidigital number, since it uses as much as digits as its factorization.
130315042520402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65157521260203.
The product of its (nonzero) digits is 28800, while the sum is 32.
The spelling of 130315042520402 in words is "one hundred thirty trillion, three hundred fifteen billion, forty-two million, five hundred twenty thousand, four hundred two".
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