Base | Representation |
---|---|
bin | 11101101000011010000011… |
… | …011101000010010001010000 |
3 | 122002102110222001111201120000 |
4 | 131220122003131002101100 |
5 | 114040131032344401000 |
6 | 1141100121234450000 |
7 | 36310213433305221 |
oct | 3550320335022120 |
9 | 562373861451500 |
10 | 130320103122000 |
11 | 38584499857640 |
12 | 12748aaaa33900 |
13 | 579419625624c |
14 | 242775318b248 |
15 | 100edd1a93000 |
hex | 768683742450 |
130320103122000 has 1600 divisors, whose sum is σ = 523478872350720. Its totient is φ = 30984218496000.
The previous prime is 130320103121983. The next prime is 130320103122023. The reversal of 130320103122000 is 221301023031.
130320103122000 is a `hidden beast` number, since 1 + 3 + 0 + 320 + 10 + 312 + 20 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 319 ways as a sum of consecutive naturals, for example, 28535163717 + ... + 28535168283.
Almost surely, 2130320103122000 is an apocalyptic number.
130320103122000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130320103122000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (261739436175360).
130320103122000 is an abundant number, since it is smaller than the sum of its proper divisors (393158769228720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130320103122000 is a wasteful number, since it uses less digits than its factorization.
130320103122000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4919 (or 4894 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 130320103122000 its reverse (221301023031), we get a palindrome (130541404145031).
It can be divided in two parts, 1303201031 and 22000, that added together give a palindrome (1303223031).
The spelling of 130320103122000 in words is "one hundred thirty trillion, three hundred twenty billion, one hundred three million, one hundred twenty-two thousand".
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