Base | Representation |
---|---|
bin | 1011110110100100001011… |
… | …1000011101110011101001 |
3 | 1201010212000011122021000111 |
4 | 2331221002320131303221 |
5 | 3202004121013440343 |
6 | 43414501544534321 |
7 | 2513351263501123 |
oct | 275510270356351 |
9 | 51125004567014 |
10 | 13032052874473 |
11 | 41749541147a6 |
12 | 15658481813a1 |
13 | 736bc044b429 |
14 | 330a7cd70213 |
15 | 178ed8619c9d |
hex | bda42e1dce9 |
13032052874473 has 2 divisors, whose sum is σ = 13032052874474. Its totient is φ = 13032052874472.
The previous prime is 13032052874411. The next prime is 13032052874479. The reversal of 13032052874473 is 37447825023031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7380958771264 + 5651094103209 = 2716792^2 + 2377203^2 .
It is a cyclic number.
It is not a de Polignac number, because 13032052874473 - 241 = 10833029618921 is a prime.
It is not a weakly prime, because it can be changed into another prime (13032052874479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516026437236 + 6516026437237.
It is an arithmetic number, because the mean of its divisors is an integer number (6516026437237).
Almost surely, 213032052874473 is an apocalyptic number.
It is an amenable number.
13032052874473 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032052874473 is an equidigital number, since it uses as much as digits as its factorization.
13032052874473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3386880, while the sum is 49.
The spelling of 13032052874473 in words is "thirteen trillion, thirty-two billion, fifty-two million, eight hundred seventy-four thousand, four hundred seventy-three".
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