Base | Representation |
---|---|
bin | 11000010001100011… |
… | …00001000010111011 |
3 | 1020122020012021102101 |
4 | 30020301201002323 |
5 | 203142204200102 |
6 | 5553055044231 |
7 | 640643010502 |
oct | 141061410273 |
9 | 36566167371 |
10 | 13032100027 |
11 | 558830a701 |
12 | 2638510677 |
13 | 12c8c307bb |
14 | 8b8b23839 |
15 | 514192e87 |
hex | 308c610bb |
13032100027 has 2 divisors, whose sum is σ = 13032100028. Its totient is φ = 13032100026.
The previous prime is 13032099991. The next prime is 13032100073. The reversal of 13032100027 is 72000123031.
It is a weak prime.
It is an emirp because it is prime and its reverse (72000123031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13032100027 - 211 = 13032097979 is a prime.
It is a super-2 number, since 2×130321000272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13032099977 and 13032100013.
It is not a weakly prime, because it can be changed into another prime (13032100097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516050013 + 6516050014.
It is an arithmetic number, because the mean of its divisors is an integer number (6516050014).
Almost surely, 213032100027 is an apocalyptic number.
13032100027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032100027 is an equidigital number, since it uses as much as digits as its factorization.
13032100027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 19.
Adding to 13032100027 its reverse (72000123031), we get a palindrome (85032223058).
The spelling of 13032100027 in words is "thirteen billion, thirty-two million, one hundred thousand, twenty-seven".
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