1303211133001 has 2 divisors, whose sum is σ = 1303211133002. Its totient is φ = 1303211133000.

The previous prime is 1303211132969. The next prime is 1303211133023. The reversal of 1303211133001 is 1003311123031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1159153689600 + 144057443401 = 1076640^2 + 379549^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303211133001 - 2⁵ = 1303211132969 is a prime.

It is a super-2 number, since 2×1303211133001² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1303211133001.

It is not a weakly prime, because it can be changed into another prime (1303211433001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651605566500 + 651605566501.

It is an arithmetic number, because the mean of its divisors is an integer number (651605566501).

Almost surely, 2^{1303211133001} is an apocalyptic number.

It is an amenable number.

1303211133001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303211133001 is an equidigital number, since it uses as much as digits as its factorization.

1303211133001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1303211133001 its reverse (1003311123031), we get a palindrome (2306522256032).

The spelling of 1303211133001 in words is "one trillion, three hundred three billion, two hundred eleven million, one hundred thirty-three thousand, one".