Base | Representation |
---|---|
bin | 11101101000011011110101… |
… | …101001111101100011010011 |
3 | 122002102122220120210011022222 |
4 | 131220123311221331203103 |
5 | 114040143443343110141 |
6 | 1141101035321051255 |
7 | 36310312060046264 |
oct | 3550336551754323 |
9 | 562378816704288 |
10 | 130322019113171 |
11 | 38585292335116 |
12 | 12749344626b2b |
13 | 5794410198632 |
14 | 242789581896b |
15 | 100ee94dae14b |
hex | 7686f5a7d8d3 |
130322019113171 has 2 divisors, whose sum is σ = 130322019113172. Its totient is φ = 130322019113170.
The previous prime is 130322019113137. The next prime is 130322019113191. The reversal of 130322019113171 is 171311910223031.
It is a strong prime.
It is an emirp because it is prime and its reverse (171311910223031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130322019113171 - 230 = 130320945371347 is a prime.
It is not a weakly prime, because it can be changed into another prime (130322019113191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65161009556585 + 65161009556586.
It is an arithmetic number, because the mean of its divisors is an integer number (65161009556586).
Almost surely, 2130322019113171 is an apocalyptic number.
130322019113171 is a deficient number, since it is larger than the sum of its proper divisors (1).
130322019113171 is an equidigital number, since it uses as much as digits as its factorization.
130322019113171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 35.
The spelling of 130322019113171 in words is "one hundred thirty trillion, three hundred twenty-two billion, nineteen million, one hundred thirteen thousand, one hundred seventy-one".
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