Base | Representation |
---|---|
bin | 11101101000011101001001… |
… | …110100010001101111010010 |
3 | 122002102210112222200200211221 |
4 | 131220131021310101233102 |
5 | 114040204341330302232 |
6 | 1141101431400555254 |
7 | 36310362053551063 |
oct | 3550351164215722 |
9 | 562383488620757 |
10 | 130323431103442 |
11 | 38585947373325 |
12 | 12749679482b2a |
13 | 57945a6884835 |
14 | 242798b16c56a |
15 | 1010028d21897 |
hex | 768749d11bd2 |
130323431103442 has 16 divisors (see below), whose sum is σ = 197026741435392. Its totient is φ = 64647862821360.
The previous prime is 130323431103311. The next prime is 130323431103449. The reversal of 130323431103442 is 244301134323031.
It is a junction number, because it is equal to n+sod(n) for n = 130323431103398 and 130323431103407.
It is not an unprimeable number, because it can be changed into a prime (130323431103449) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18668217 + ... + 24680947.
It is an arithmetic number, because the mean of its divisors is an integer number (12314171339712).
Almost surely, 2130323431103442 is an apocalyptic number.
130323431103442 is a deficient number, since it is larger than the sum of its proper divisors (66703310331950).
130323431103442 is a wasteful number, since it uses less digits than its factorization.
130323431103442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6098193.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 130323431103442 its reverse (244301134323031), we get a palindrome (374624565426473).
The spelling of 130323431103442 in words is "one hundred thirty trillion, three hundred twenty-three billion, four hundred thirty-one million, one hundred three thousand, four hundred forty-two".
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