Base | Representation |
---|---|
bin | 11101101000011101110001… |
… | …110100000101010111100011 |
3 | 122002102212021202100221220001 |
4 | 131220131301310011113203 |
5 | 114040212230122011121 |
6 | 1141102022131400431 |
7 | 36310414512356023 |
oct | 3550356164052743 |
9 | 562385252327801 |
10 | 130324102141411 |
11 | 38586161131062 |
12 | 12749826153117 |
13 | 57946828c3519 |
14 | 2427a12327a83 |
15 | 1010067bc2991 |
hex | 768771d055e3 |
130324102141411 has 2 divisors, whose sum is σ = 130324102141412. Its totient is φ = 130324102141410.
The previous prime is 130324102141399. The next prime is 130324102141421. The reversal of 130324102141411 is 114141201423031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130324102141411 - 239 = 129774346327523 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130324102141411.
It is not a weakly prime, because it can be changed into another prime (130324102141421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65162051070705 + 65162051070706.
It is an arithmetic number, because the mean of its divisors is an integer number (65162051070706).
Almost surely, 2130324102141411 is an apocalyptic number.
130324102141411 is a deficient number, since it is larger than the sum of its proper divisors (1).
130324102141411 is an equidigital number, since it uses as much as digits as its factorization.
130324102141411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 130324102141411 its reverse (114141201423031), we get a palindrome (244465303564442).
The spelling of 130324102141411 in words is "one hundred thirty trillion, three hundred twenty-four billion, one hundred two million, one hundred forty-one thousand, four hundred eleven".
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