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130324114413169 is a prime number
BaseRepresentation
bin11101101000011101110010…
…100010111001011001110001
3122002102212022121110102120121
4131220131302202321121301
5114040212241242210134
61141102023250410241
736310415021566525
oct3550356242713161
9562385277412517
10130324114413169
1138586168053006
121274982a290981
1357946852cc111
142427a13bddd85
151010068ce8ab4
hex7687728b9671

130324114413169 has 2 divisors, whose sum is σ = 130324114413170. Its totient is φ = 130324114413168.

The previous prime is 130324114413121. The next prime is 130324114413211. The reversal of 130324114413169 is 961314411423031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116975321453169 + 13348792960000 = 10815513^2 + 3653600^2 .

It is an emirp because it is prime and its reverse (961314411423031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130324114413169 - 215 = 130324114380401 is a prime.

It is a super-2 number, since 2×1303241144131692 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130324114416169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65162057206584 + 65162057206585.

It is an arithmetic number, because the mean of its divisors is an integer number (65162057206585).

Almost surely, 2130324114413169 is an apocalyptic number.

It is an amenable number.

130324114413169 is a deficient number, since it is larger than the sum of its proper divisors (1).

130324114413169 is an equidigital number, since it uses as much as digits as its factorization.

130324114413169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 186624, while the sum is 43.

The spelling of 130324114413169 in words is "one hundred thirty trillion, three hundred twenty-four billion, one hundred fourteen million, four hundred thirteen thousand, one hundred sixty-nine".