Base | Representation |
---|---|
bin | 1011110110100101100101… |
… | …1111101000011001110001 |
3 | 1201010212222121111001000111 |
4 | 2331221121133220121301 |
5 | 3202010410123141431 |
6 | 43415003340021321 |
7 | 2513363551162561 |
oct | 275513137503161 |
9 | 51125877431014 |
10 | 13032432240241 |
11 | 4175029276927 |
12 | 1565933231841 |
13 | 736c50c16a0b |
14 | 330ab74c2da1 |
15 | 17900baa47b1 |
hex | bda597e8671 |
13032432240241 has 2 divisors, whose sum is σ = 13032432240242. Its totient is φ = 13032432240240.
The previous prime is 13032432240199. The next prime is 13032432240329. The reversal of 13032432240241 is 14204223423031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10984087350625 + 2048344889616 = 3314225^2 + 1431204^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13032432240241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13032432243241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516216120120 + 6516216120121.
It is an arithmetic number, because the mean of its divisors is an integer number (6516216120121).
Almost surely, 213032432240241 is an apocalyptic number.
It is an amenable number.
13032432240241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032432240241 is an equidigital number, since it uses as much as digits as its factorization.
13032432240241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13032432240241 its reverse (14204223423031), we get a palindrome (27236655663272).
The spelling of 13032432240241 in words is "thirteen trillion, thirty-two billion, four hundred thirty-two million, two hundred forty thousand, two hundred forty-one".
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