Base | Representation |
---|---|
bin | 11101101000100011010001… |
… | …100001100100011010010011 |
3 | 122002110102111222121220212001 |
4 | 131220203101201210122103 |
5 | 114040311321213232414 |
6 | 1141104435440414431 |
7 | 36311013652616104 |
oct | 3550432141443223 |
9 | 562412458556761 |
10 | 130330002867859 |
11 | 38588709a17193 |
12 | 1274a9b2317417 |
13 | 57950b3241332 |
14 | 2428011c943ab |
15 | 10102b0c4b074 |
hex | 7688d1864693 |
130330002867859 has 2 divisors, whose sum is σ = 130330002867860. Its totient is φ = 130330002867858.
The previous prime is 130330002867833. The next prime is 130330002867871. The reversal of 130330002867859 is 958768200033031.
It is a strong prime.
It is an emirp because it is prime and its reverse (958768200033031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130330002867859 - 231 = 130327855384211 is a prime.
It is a super-2 number, since 2×1303300028678592 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130330002867059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65165001433929 + 65165001433930.
It is an arithmetic number, because the mean of its divisors is an integer number (65165001433930).
Almost surely, 2130330002867859 is an apocalyptic number.
130330002867859 is a deficient number, since it is larger than the sum of its proper divisors (1).
130330002867859 is an equidigital number, since it uses as much as digits as its factorization.
130330002867859 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6531840, while the sum is 55.
The spelling of 130330002867859 in words is "one hundred thirty trillion, three hundred thirty billion, two million, eight hundred sixty-seven thousand, eight hundred fifty-nine".
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