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130330443511 = 175374347087
BaseRepresentation
bin111100101100001001…
…1001011111011110111
3110110101221201111220101
41321120103023323313
54113404043143021
6135512321414531
712262465330342
oct1713023137367
9413357644811
10130330443511
1150300157244
122131349a447
13c3a04a1438
146445325459
1535cbd87a91
hex1e584cbef7

130330443511 has 4 divisors (see below), whose sum is σ = 130404792352. Its totient is φ = 130256094672.

The previous prime is 130330443491. The next prime is 130330443533. The reversal of 130330443511 is 115344033031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130330443511 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130330443511.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130330443011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37171791 + ... + 37175296.

It is an arithmetic number, because the mean of its divisors is an integer number (32601198088).

Almost surely, 2130330443511 is an apocalyptic number.

130330443511 is a deficient number, since it is larger than the sum of its proper divisors (74348841).

130330443511 is an equidigital number, since it uses as much as digits as its factorization.

130330443511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74348840.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 130330443511 its reverse (115344033031), we get a palindrome (245674476542).

The spelling of 130330443511 in words is "one hundred thirty billion, three hundred thirty million, four hundred forty-three thousand, five hundred eleven".

Divisors: 1 1753 74347087 130330443511