Base | Representation |
---|---|
bin | 1011110110101000000101… |
… | …0010111011101111001001 |
3 | 1201010221201010222202110212 |
4 | 2331222001102323233021 |
5 | 3202013242100001301 |
6 | 43415153512250505 |
7 | 2513416240065611 |
oct | 275520122735711 |
9 | 51127633882425 |
10 | 13033100000201 |
11 | 41753411a5866 |
12 | 1565a9a9a0a35 |
13 | 737029378658 |
14 | 330b3c067a41 |
15 | 17904a5094bb |
hex | bda814bbbc9 |
13033100000201 has 2 divisors, whose sum is σ = 13033100000202. Its totient is φ = 13033100000200.
The previous prime is 13033100000197. The next prime is 13033100000231. The reversal of 13033100000201 is 10200000133031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12986480712976 + 46619287225 = 3603676^2 + 215915^2 .
It is a cyclic number.
It is not a de Polignac number, because 13033100000201 - 22 = 13033100000197 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (13033100000231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516550000100 + 6516550000101.
It is an arithmetic number, because the mean of its divisors is an integer number (6516550000101).
Almost surely, 213033100000201 is an apocalyptic number.
It is an amenable number.
13033100000201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033100000201 is an equidigital number, since it uses as much as digits as its factorization.
13033100000201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 13033100000201 its reverse (10200000133031), we get a palindrome (23233100133232).
The spelling of 13033100000201 in words is "thirteen trillion, thirty-three billion, one hundred million, two hundred one", and thus it is an aban number.
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